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Re: Select a node by name
- From: Oleg Tkachenko <olegt at multiconn dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 04 Oct 2002 19:35:55 +0300
- Subject: Re: [xsl] Select a node by name
- Organization: Multiconn International Ltd
- References: <3D9DBF21.1050302@software.b.uunet.de>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Andreas Schlegel wrote:
<persons>
<person name="Bill" job="Developer"/>
<person name="Steve" job="Admin"/>
<person name="Betty" job="CEO"/>
</persons>
A statement like <xsl:value-of select="person"/> won't help because I
have a lot of nodes of the type PERSON.
If I have a node already selected I may use <xsl:value-of select="@name"/>
It's no problem to do it by for each ( <xsl:for-each select="person"> ).
But I look for a way to pick a person out of the list, i.e. "Betty".
That's xpath basics, what you need is just person[@name='Betty'], what
means in english "Select all person elements children of the current
node, which have attribute name with string value 'Betty'".
For more info see xpath recommendation at http://www.w3.org/TR/xpath.
--
Oleg Tkachenko
eXperanto team
Multiconn International, Israel
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