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RE: SNR calculations (was Re: setup.exe missing from FTP site)


On Sat, 26 May 2007, Dave Korn wrote:

> On 26 May 2007 22:47, Brian Dessent wrote:
>
> > Linda Walsh wrote:
> >
> >>>   I prefer to express that as an SNR of -18dB :-)
> >> ---
> >>      Could you please show your work!
> >>
> >>      I arrived at -9dB. Work:
> >>          For each doubling/halving of power one adjusts by ~(+/-)3dB.
> >>              (note: "3" is approximation of 10*log(2) or,
> >>                     to 7 decimal places, 3.010900)
> >>                 so 1 unit / 2 units of signal would be -3dB,
> >>                    1 unit / 4 units: -6dB,
> >>                    1 unit / 8 units: -9dB
> >>
> >>      From my limited understanding, -18dB would be a reduction of 6
> >> factors of 2, or a 1:64 signal/noise ratio.
> >
> > Typically you use dB to compare the amount of power in a signal relative
> > to a fixed reference; in the case of electronics a common reference is
> > 1mV, or 0 dBmV. Since power in a signal is proportional to V^2, when you
> > compute dBmV from a voltage level it's 20*log(v) due to the power of 2.
> >
> > But when you just want to use dB to represent a unitless ratio, then I
> > agree with you it's simply 10*log(ratio).
> >
> > Brian
>
>
>   For purposes of humour, the larger magnitude number is always better.
> Hence I counted 6dB per doubling.  The fact that it was technically
> correct is a mere beneficent side-effect!

Also, you must've anticipated this discussion, which surely lowered the
SNR to -18db or less... :-)
	Igor
-- 
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