b19.1: question about "wait for job"
Christopher G. Faylor
Sat Sep 5 18:37:00 GMT 1998
In article <35EFD8AE.856648C4.email@example.com>,
Schzen Ooi <firstname.lastname@example.org> wrote:
>Suppose, you had a script in, say, "d:/usr/local/bin/which" is defined
>>for p in $PATH; do
>> if [ -f "$p/$1" ]; then
>> ls "$p/$1"
>> exit 0
>>#type -p $1
>to demonstrate the output below, and running it [might] give the
>>bash2$ whereis ls
>>//d/usr/local/bin/whereis: waitforjob: no children
>Changing the "#!/bin/sh" to "#!/usr/local/bin/bash" makes the message go
>I have the following in d:/bin/sh.exe,
>and d:/usr/local/bin/bash.exe for convenience and they are just
>and mount paths defined with
>"d:\usr\H-i386-cygwin32\bin" -> "/bin"
>"d:\usr" -> "/usr"
>if this detail is significant.
>What does the waitforjob mean?
It usually means that ash is confused by pids > 32767. Try running a coolview
version of the .dll: http://www.lexa.ru/sos .
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