shell script bug
Chris Faylor
cgf@cygnus.com
Fri Jul 28 09:58:00 GMT 2000
On Fri, Jul 28, 2000 at 09:30:13AM -0700, Noel Yap wrote:
>I have the following script asdf.sh:
>#!/bin/sh
>
>if [ $# = 1 ]
>then
> for v in "$@"
> do
> echo $# should be 1
> echo "$v"
> done
>else
> for v in "$@"
> do
> echo $# isn\'t be 1
> ./asdf.sh "$v"
> done
>fi
>
>Under bash, the output of the script is:
>5 isn't 1
>5 isn't 1
>5 isn't 1
>5 isn't 1
>5 isn't 1
>
>Under sh, there is no output.
...which is what I'd expect.
I tried this on a couple of machines and the behavior is inconsistent.
Some print "0 isn't be 1" (sic) and some print nothing.
I would consider the triggering of the for-loop when there are no
arguments supplied to the shell script to be a bug.
cgf
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