Percent of CPU this job got > 100%

[Christopher Faylor]

On Thu, Oct 16, 2003 at 08:38:33AM +0200, Alex Vinokur wrote:
>===========================================
>Windows 2000 Professional
>CYGWIN_NT-5.0 1.5.4(0.94/3/2)
>GNU time 1.7
>===========================================
>
>$ /bin/time -v a 1000
>
> Command being timed: "a 1000"
> User time (seconds): 0.03
> System time (seconds): 0.03
> Percent of CPU this job got: 133%
> Elapsed (wall clock) time (h:mm:ss or m:ss): 0:00.04
> [--omitted--]
> Exit status: 0
>
>
>
>$ info time
>[snip]
>`P'
>     Percentage of the CPU that this job got.  This is just user +
>     system times divied by the total running time.
>[snip]
>
>
>Percent of CPU this job got > 100%.
>How to interpret that?

Automatic, built-in meanness at no extra charge.

cgf

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