python-2.4.3-1 problem with urllib2
Chris AtLee
chris@atlee.ca
Thu Jun 15 19:05:00 GMT 2006
The attached python script works fine under python-2.4.1-1. Under
python-2.4.3-1, I get this output:
Using urllib.urlopen
......................................................................................................................................................
Using urllib2.urlopen
.............................................................................................Traceback
(most recent call last):
File "test-urllib.py", line 42, in ?
doRequest2("http://localhost:8010")
File "test-urllib.py", line 16, in doRequest2
f = urllib2.urlopen(url)
File "/usr/lib/python2.4/urllib2.py", line 130, in urlopen
return _opener.open(url, data)
File "/usr/lib/python2.4/urllib2.py", line 358, in open
response = self._open(req, data)
File "/usr/lib/python2.4/urllib2.py", line 376, in _open
'_open', req)
File "/usr/lib/python2.4/urllib2.py", line 337, in _call_chain
result = func(*args)
File "/usr/lib/python2.4/urllib2.py", line 1021, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib/python2.4/urllib2.py", line 996, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error unable to select on socket>
This happens after a consistent number of requests on my machine.
Cheers,
Chris
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