[SOLVED] Re: cygwin's [g]make 3.81 seems not to understand conditionals

[Carlo Florendo]

Carlo Florendo wrote:
> David Rothenberger wrote:
>> On 7/18/2007 9:03 PM, Carlo Florendo wrote:
>>> I've got (and attached) this simple Makefile that checks the build 
>>> platform of a machine.
>>>
>>> Here's the cut-and-pasted content of the Makefile:
>>>
>>> PLATFORM=$(shell uname -s | cut -f 1 -d " " | cut -f 1 -d "_");
>>
>> Try removing the trailing semicolon. It is not removed by make, so 
>> PLATFORM ends up being "CYGWIN;".
> 
> Bingo.  That did it!
> 
> So does that mean that make 3.80 was wrong then?

Please ignore this, sorry.  Both have the correct behaviour.

When expanded under Linux, the make statements become

ifeq ("Linux;", "CYGWIN)
     echo cygwin;
else
     echo linux;
endif

it will "correctly" output "linux"  but it got to the else conditional only 
because "Linux;" != "CYGWIN.

The trailing semi-colon confused me.  I was treating the Makefile as a bash 
script.


Thanks, David!

Best Regards,

Carlo

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Carlo Florendo
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Astra Philippines Inc.
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Philippines
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