bug in mbrtowc?

[Pedro Izecksohn]

  From the "Linux Programmer’s Manual" (release 3.15 of the Linux man-pages):
"If the n bytes starting at s do not contain a complete multibyte
character,  mbrtowc()  returns  (size_t) -2."

On Mon, Jul 27, 2009 at 6:56 PM, Andy Koppe wrote:
> I've encountered what looks like a bug in mbrtowc's handling of UTF-8.
> Here's an example:
>
> #include <stdio.h>
> #include <locale.h>
> #include <stdlib.h>
> #include <wchar.h>
>
> int main(void) {
>  wchar_t wc;
>  size_t ret;
>  mbstate_t s = { 0 };
>  puts(setlocale(LC_CTYPE, "en_GB.UTF-8"));
>  printf("%i\n", mbrtowc(&wc, "\xe2", 1, 0));
>  printf("%i\n", mbrtowc(&wc, "\x94", 1, 0));
>  printf("%i\n", mbrtowc(&wc, "\x84", 1, 0));
>  printf("%x\n", wc);
>  return 0;
> }
>
> The sequence E2 94 84 should translate to U+2514. Instead, the second
> and third calls to mbrtowc report encoding errors. It does work
> correctly if the three bytes are passed to mbrtowc() in one go:
>
>  printf("%i\n", mbrtowc(&wc, "\xe2\x94\x84", 3, 0));
>
> Andy

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