mk_all
René Berber
r.berber@computer.org
Fri May 20 14:27:00 GMT 2011
On 5/20/2011 3:50 AM, kathy3826 wrote:
> it must have been make all. And it seems I can bypass the one with x windows
> using source code.
No, my guess is that you used mk_all when you should have used ./mk_all
and that shows the real problem.
--
René Berber
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