Using the free(*ptr) routine and getting an exception, "Exception: STATUS_ACCESS_VIOLATION"
YZFury
yzfury@gmail.com
Mon Jan 14 05:11:00 GMT 2013
Whoops. I was making the pointer point to x instead of putting x's value in the memory that was just allocated. Now i understand that. Really sorry for a stupid syntax error question on my part. thanks for the quick reply though :). Like I said basically new to C.
Sent from my Kindle Fire
_____________________________________________
From: "Dan Kegel-2 [via Cygwin]" <ml-node+s1069669n95381h52@n5.nabble.com>
Sent: Sun Jan 13 23:52:50 EST 2013
To: YZFury <yzfury@gmail.com>
Subject: Re: Using the free(*ptr) routine and getting an exception, "Exception: STATUS_ACCESS_VIOLATION"
On Sun, Jan 13, 2013 at 7:55 PM, YZFury <[hidden email]> wrote:
> int *ptr = malloc(sizeof(*ptr));
> int x = 87;
> ptr = &x;
> printf("%d", *ptr);
> free(ptr);//it goes wrong here
As you probably know, you can't call free() on a pointer
that didn't come from malloc(). ptr's first value came from malloc,
but you overwrote that with
ptr = &x;
Perhaps you meant
*ptr = x;
So you're a level of indirection off.
- Dan
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