How does make determine which shells to invoke when executing external commands?
Warren Young
warren@etr-usa.com
Thu Jun 6 16:25:00 GMT 2013
On 6/5/2013 20:43, Hua Ai wrote:
> I thought this is a cygwin issue since windows
> commands were invoked.
Cygwin make should *always* be using /bin/sh to interpret commands,
unless you've overridden it with SHELL.
Type this into a Makefile:
all:
@echo Shell is $(SHELL)
Then say "make" in that directory. It should confirm my assertion.
If it tells you something different on a problem machine, say "make
--version" and verify that it says "Built for i686-pc-cygwin".
> We don't have MinGW, but we do have multiple versions of a software
> (development tools from Altera) installed on these computers, which
> all contains a copy of cygwin (different versions but all with make).
Are you *certain* Altera is shipping Cygwin GNU make and not MinGW make?
Either way, you're kind of in a bind.
If Altera is shipping MinGW GNU make, you have the conflict I originally
proposed.
If they are in fact shipping Cygwin, you have this problem:
http://www.cygwin.com/faq.html#faq.using.multiple-copies
(Items 4.19 through 4.23.)
> This makefile however was run from a standalone cygwin.
What does it say when you say "which make"?
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