B.20.1 bash question - paths sent to #!

[Doug Wyatt]

Hi,

I believe I've seen some recent postings about converting pathname
formats - check the archives at < http://sourceware.cygnus.com/ml/cygwin/ >.

Quite some time back, I tried using the AS Perl with Cygwin but the final
straw was when I found that AS Perl didn't implement fork and exec.
I'd recommend trying the Cygwin port of Perl; it's fully compatible with
Cygwin and seems very stable.  Look to < http://cygutils.netpedia.net/ > if
you want to try it.

Regards,
Doug Wyatt

> Hello -
> 
> I looked in the archives and did not see a solution to this issue:
> 
> I have 3 drives on my NT 4.0 system: C: D: E:.
> I have a perl script that has "#!/usr/bin/perl" in it.
> I am trying to put the perl script in my path, so that I can run it from
> any drive.
> I am using ActiveState Perl.
> 
> Here is the situation.  First, my perl script is called "pop3", and it
> resides in /e/perl/bin.  If I put /e/perl/bin in my path, then I believe
> that bash calls /usr/bin/perl with the file name as /e/perl/bin/pop3.
> However, AS Perl can't interpret this file name and gives a "file not found"
> error.
> 
> I tried putting /perl/bin/ in my path, and this works, as long as I am "on"
> the e drive.  When I go to another drive, /perl/bin does not exist, and
> calling pop3 fails again.
> 
> So what I'd like is to have bash convert the Posix path of the called script
> to win32 when using the #! syntax, so that AS Perl (and other interpreters)
> will have a path it can work with.  Is there a workaround?
> 
> I hope this makes sense.  Let me know if can clarify.
> -----------------
> Al and Patricia
> 
> 
> 
> 
> 
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